Question

A metal ball of heat capacity 50J/°C loses 2000 J of heat. By how much will its temperature fall?

Answer 1

Heat capacity of ball = 50 J °C^-1
Heat lost Q = 200 J
Fall in temperature t =?

Heat Capacity = `"Q"/"t"`

50 = `2000/"t"`

t = `2000/50`

t = 40° C