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प्रश्न
A metal sphere cools from 66° C to 57° C in 10 minutes and to 44° C in the next 10 minutes. The ratio of fall of temperature of first 10 minutes to next ten minutes is ____________.
पर्याय
`13/9`
`7/6`
`9/13`
`4/7`
MCQ
रिकाम्या जागा भरा
उत्तर
A metal sphere cools from 66° C to 57° C in 10 minutes and to 44° C in the next 10 minutes. The ratio of fall of temperature of first 10 minutes to next ten minutes is `9/13`.
Explanation:
`"R"_1 = (66 - 57)/10 = 9/10`
`"R"_2 = (57° - 44°)/10 = 13/10`
`therefore "R"_1/"R"_2 = (9//10)/(13//10) = 9/13 `
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Newton’s Law of Cooling
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