Question

A metal sphere cools from 66° C to 57° C in 10 minutes and to 44° C in the next 10 minutes. The ratio of fall of temperature of first 10 minutes to next ten minutes is ____________.

Options

• `13/9`

• `7/6`

• `9/13`

• `4/7`

Answer 1

A metal sphere cools from 66° C to 57° C in 10 minutes and to 44° C in the next 10 minutes. The ratio of fall of temperature of first 10 minutes to next ten minutes is `9/13`.

Explanation:

`"R"_1 = (66 - 57)/10 = 9/10`

`"R"_2 = (57° - 44°)/10 = 13/10`

`therefore "R"_1/"R"_2 = (9//10)/(13//10) = 9/13 `