Question

A person throws a ball with a speed of 10 m/s at an angle of 30° with horizontally from the top of a 10 m high tower. The distance of the ball from the foot of the tower after falling on the ground will be ______.

पर्याय

• 7 m

• 8.6 m

• 9.6 m

• 10 m

Answer 1

A person throws a ball with a speed of 10 m/s at an angle of 30° with horizontally from the top of a 10 m high tower. The distance of the ball from the foot of the tower after falling on the ground will be 8.6 m.

Explanation:

 

When the ball is 10m above the ground, it will be at point P. As a result, we must determine the distance OP, which can be determined immediately by treating it as a projectile on a levelled plane OX.

Therefore, the maximum range, OP = `R = (u^2 sin2theta)/g`

= `(10^2 xx sin(2 xx 30^circ))/10`

= `(10sqrt3)/2 = 5sqrt3` = 8.6 m