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प्रश्न
उत्तर
(i) Given: Heat Capacity, me = 966 J/°C
Heat energy required, Q = m x C x change in temperature
= 966 x 15 = 14490 J
(ii) Q = m x C x T
Specific heat capacity, C = `"Q"/("m"Δ "T")`
= `14490/(2 xx 15)`
= 483 Jkg-1 °C-1
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संबंधित प्रश्न
Differentiate between heat and temperature.
What is a calorimeter?
How will you determine the specific heat capacity of a liquid like olive oil by the method of mixtures?
1300 J of heat energy is supplied to raise the temperature of 6.5 kg of lead from 20° C to 40°C. Calculate the specific heat capacity of lead.
(i) Define Calorimetry.
(ii) Name the material used for making a Calorimeter.
(iii) Why is a Calorimeter made up of thin sheets of the above material answered in (ii).
A mass of 200 g of mercury at 100°C is poured into water at 20°C. If the final temperature of the mixture is 25°C, find the mass of water. (Sp. heat cap. of mercury is 140 J/kgK).
200 g of hot water at 80°C is added to 300 g of cold water at 10 °C. Calculate the final temperature of the mixture of water. Consider the heat taken by the container to be negligible. [specific heat capacity of water is 4200 J kg-1 °C-1]
A copper calorimeter of mass 50g contains 100g of water at 20°C. A metallic piece of mass 250 g is heated to 100°C and is then dropped into the calorimeter. The contents of the calorimeter are well stirred and its final highest temperature is recorded to be 28 °C. If the specific heat capacity of water is 4.2 J/g°C and of copper is 0.4 J/g°C, find:
(i) the heat gained by water,
(ii) the heat gained by calorimeter,
(iii) total heat supplied by the metal piece, and
(iv) the specific heat capacity of metal.
40g of ice at 0°C is used to bring down the temperature of a certain mass of water at 60°C to 10°C. Find the mass of water used.
[Specific heat capacity of water = 4200 J kg-1 °C-1]
[Specific latent heat of fusion of ice = 336 × 103 J kg-1]
Write one characteristic property of the material chosen for making a calorimeter.
