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प्रश्न
A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the solid so formed.
उत्तर
According to the question, the solid formed is a cone whose height of a cone, h = 8 cm and radius of a cone, r = 6 cm.
Slant height of a cone, 1 = 10 cm.
So, Volume of a cone = `1/3 pir^2h = 1/3 xx 22/7 xx 6 xx 6 xx 8`
`6336/21 = 301.7 cm^3`
Now, curved surface of the area of cone = πrl
= `22/7 xx 6 xx 10`
= `1320/7`
= 188.5 cm2
Therefore, the volume and surface area of a cone are 301.7 cm3 and 188.5 cm2, respectively.
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