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प्रश्न
A rope of length 20 m is kept on a frictionless surface and a force of 5 N is applied to one of its ends. Find the tension in the rope at 5 m from this end.
पर्याय
5 N
2 N
3.75 N
4 N
MCQ
उत्तर
3.75 N
Explanation:
T = `("F"("L" - "x"))/"L"`
= `(5(20 - 5))/20`
= `75/20`
= 3.75 N
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