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Question
A rope of length 20 m is kept on a frictionless surface and a force of 5 N is applied to one of its ends. Find the tension in the rope at 5 m from this end.
Options
5 N
2 N
3.75 N
4 N
MCQ
Solution
3.75 N
Explanation:
T = `("F"("L" - "x"))/"L"`
= `(5(20 - 5))/20`
= `75/20`
= 3.75 N
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Intuitive Concept of Force
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