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प्रश्न
A solid of mass 80 g at 80°C is dropped in 400 g water at 10°C. If final temp. is 30°C, find the sp. heat cap. of the solid.
उत्तर
Let the specific heat of the solid be c.
Heat lost by solid = Heat gained by water
0.08 x c x (80 - 30) = 0.4 x 4200 x (30 - 10)
or, C = `(0.4 xx 4200 xx 20)/(0.08 xx 50) = 8400 Jkg -1 K -1
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संबंधित प्रश्न
Given below are observations on molar specific heats at room temperature of some common gases.
| Gas |
Molar specific heat (Cv) (cal mol–1 K–1) |
| Hydrogen | 4.87 |
| Nitrogen | 4.97 |
| Oxygen | 5.02 |
| Nitric oxide | 4.99 |
| Carbon monoxide | 5.01 |
| Chlorine | 6.17 |
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