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प्रश्न
A stone of mass 1 kg is whirled in horizontal circle attached at the end of a 1 m long string. If the string makes an angle of 30º with vertical, calculate the centripetal force acting on the stone.(g=9.8m/s2).
उत्तर
m = 1kg
`Tcos30^@= mg`
`T=(mg)/(cos30^@)`
`F_c = Tsin30^@`
`F_c=(mg)/cos30^@""xxsin30^@`
=mg × tan30º
= 1 × 9.8 × 1/√3
= 9.8/1.732
=5.658N
the centripetal force acting on the stone is 5.658N
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