Advertisements
Advertisements
Question
A stone of mass 1 kg is whirled in horizontal circle attached at the end of a 1 m long string. If the string makes an angle of 30º with vertical, calculate the centripetal force acting on the stone.(g=9.8m/s2).
Solution
m = 1kg
`Tcos30^@= mg`
`T=(mg)/(cos30^@)`
`F_c = Tsin30^@`
`F_c=(mg)/cos30^@""xxsin30^@`
=mg × tan30º
= 1 × 9.8 × 1/√3
= 9.8/1.732
=5.658N
the centripetal force acting on the stone is 5.658N
APPEARS IN
RELATED QUESTIONS
A coin kept at a distance of 5cm from the centre of a turntable of radius 1.5m just begins to slip when the turntable rotates at a speed of 90 r.p.m. Calculate the coefficient of static friction between the coin and the turntable.
[g = 9.8 m/s2]
The bulging of earth at the equator and flattening at the poles is due to _______.
A body of mass ‘m’ performs uniform circular motion along a circular path of radius ‘r’ with velocity ‘v’. If its angular momentum is L, then the centripetal force acting on it is :
Distinguish between centripetal and centrifugal force.
Is centrifugal force a real force?
Compare the magnitudes of centripetal and centrifugal force.
State two differences between the centripetal and centrifugal force.
A boy experiences a centrifugal force on his hand when he rotates a piece of stone tied at one end of a string, holding the other end in the hand.
The centrifugal force is ______.
The centrifugal force is ______.
The force responsible for drying clothes in a washing machine is ______.
The force experienced by a boy in the merry-go-round is a centripetal force.
