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A Student Places a 8.0 Cm Tall Object Perpendicular to the Principal Axis of a Convex Lens of Focal Length 20 Cm. - Science

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प्रश्न

A student places a 8.0 cm tall object perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. He obtains a sharp image of the object on a screen placed on the other side of the lens. What will be the nature (inverted, erect, magnified, diminished) of the image he obtains on a screen? Draw ray diagram to justify your answer.

उत्तर

Focal length of the lens, f = 20 cm
Object distance, u = −30 cm
According to the lens formula,
\[\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\]
\[ \Rightarrow \frac{1}{v} = \frac{1}{f} + \frac{1}{u}\]
\[ \Rightarrow \frac{1}{v} = \frac{1}{20} - \frac{1}{30}\]
\[ \Rightarrow v = 60 cm\]
\[\text{ Magnification }, m = \frac{v}{u}\]
\[ \Rightarrow m = \frac{60}{\left( - 30 \right)} = - 2\]
Hence, the image formed is real, inverted and magnified.

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2014-2015 (March) Foreign Set 3

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संबंधित प्रश्‍न

Analyse the following observation table showing variation of image-distance (v) with object-distance (u) in case of a convex lens and answer the questions that follow without doing any calculations : 

S. No. Object-Distance
u (cm)
Image-Distance
v (cm)
1 –100 +25
2 –60 +30
3 –40 +40
4 –30 +60
5 –25 +100
6 –15 +120

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(b) Write the serial number of the observation which is not correct. On what basis have you arrived at this conclusion?

(c) Select an appropriate scale and draw a ray diagram for the observation at S.No. 2. Also find the approximate value of magnification.
 


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f the image formed by a convex lens is of the same size as that of the object, what is the position of the image with respect to the lens? 


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An object is placed at a distance equal to 2f in front of a convex lens. Draw a labelled ray diagram to show the formation of image. State two characteristics of the image formed.


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