Advertisements
Advertisements
प्रश्न
A survey conducted on 20 households in a locality by a group of students resulted in the following frequency table for the number of family members in a household:
Family size | 1 – 3 | 3 – 5 | 5 – 7 | 7 – 9 | 9 – 11 |
Numbers of Families | 7 | 8 | 2 | 2 | 1 |
Find the median of this data.
उत्तर
Family Size |
Number of families (f) |
Cumulative frequency (Cf) |
1 – 3 | 7 | 7 |
3 – 5 | 8 | 15 |
5 – 7 | 2 | 17 |
7 – 9 | 2 | 19 |
9 – 11 | 1 | 20 = N |
Median = `N^(th)/2` term
= 10th term
Median class = 3 – 5
Median = `l + (N/2 - Cf)/f xx h`
= `3 + (10 - 7)/8 xx 2`
= 3 + 0.75
∴ Median = 3.75
APPEARS IN
संबंधित प्रश्न
If the median of the distribution given below is 28.5, find the values of x and y.
Class interval | Frequency |
0 - 10 | 5 |
10 - 20 | x |
20 - 30 | 20 |
30 - 40 | 15 |
40 - 50 | y |
50 - 60 | 5 |
Total | 60 |
For a certain frequency distribution, the values of mean and median are 72 and 78 respectively. Find the value of mode.
The following is the distribution of height of students of a certain class in a certain city:
Height (in cm): | 160 - 162 | 163 - 165 | 166 - 168 | 169 - 171 | 172 - 174 |
No. of students: | 15 | 118 | 142 | 127 | 18 |
Find the median height.
A data has 25 observations arranged in a descending order. Which observation represents the median?
The Median when it is given that mode and mean are 8 and 9 respectively, is ______.
Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median
Distance (in m) |
0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
Number of Students |
40 | 80 | 62 | 38 | 30 |
Yoga is an ancient practice which is a form of meditation and exercise. By practising yoga, we not even make our body healthy but also achieve inner peace and calmness. The International Yoga Day is celebrated on the 21st of June every year since 2015. |
Age Group | 15 – 25 | 25 – 35 | 35 – 45 | 45 –55 | 55 –65 | 65 –75 | 75 – 85 |
Number of People |
8 | 10 | 15 | 25 | 40 | 24 | 18 |
Based on the above, find the following:
- Find the median age of people enrolled for the camp.
- If x more people of the age group 65 – 75 had enrolled for the camp, the mean age would have been 58. Find the value of x.
Find the median of the following frequency distribution:
Class: | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
Frequency: | 6 | 8 | 5 | 9 | 7 |
The median of 100 observations grouped in classes of equal width is 25. If the median class interval is 20 –30 and the number of observations less than 20 is 45, then the frequency of median class is ______.
The empirical relation between the mode, median and mean of a distribution is ______.