Advertisements
Advertisements
प्रश्न
Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median
| Distance (in m) |
0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
| Number of Students |
40 | 80 | 62 | 38 | 30 |
उत्तर
| Distance (in m) |
0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
| Number of Students |
40 | 80 | 62 | 38 | 30 |
| `cf` | 40 | 120 | 182 | 220 | 250 |
`n/2 = 250/2` = 125 ⇒ median class is 2 – 3, `l` = 2, `h` = 1, `cf` = 120, `f` = 62
Median = `l + (n/2 - cf)/f xx i`
= `2 + 5/62`
= `129/62 = 2 5/62` m or 2.8 m
50% of students jumped below `2 5/62` m and 50% above it.
APPEARS IN
संबंधित प्रश्न
The following table shows ages of 3000 patients getting medical treatment in a hospital on a particular day :
| Age (in years) | No. of Patients |
| 10-20 | 60 |
| 20-30 | 42 |
| 30-40 | 55 |
| 40-50 | 70 |
| 50-60 | 53 |
| 60-70 | 20 |
Find the median age of the patients.
The table below shows the salaries of 280 persons :
| Salary (In thousand Rs) | No. of Persons |
| 5 – 10 | 49 |
| 10 – 15 | 133 |
| 15 – 20 | 63 |
| 20 – 25 | 15 |
| 25 – 30 | 6 |
| 30 – 35 | 7 |
| 35 – 40 | 4 |
| 40 – 45 | 2 |
| 45 – 50 | 1 |
Calculate the median salary of the data.
Calculate the missing frequency from the following distribution, it being given that the median of the distribution is 24.
| Age in years | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
| No. of persons | 5 | 25 | ? | 18 | 7 |
A student got the following marks in 9 questions of a question paper.
3, 5, 7, 3, 8, 0, 1, 4 and 6.
Find the median of these marks.
The median of the following data is 16. Find the missing frequencies a and b if the total of frequencies is 70.
| Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 | 35 – 40 |
| Frequency | 12 | a | 12 | 15 | b | 6 | 6 | 4 |
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
| Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
| Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
The arithmetic mean and mode of a data are 24 and 12 respectively, then its median is
Find the median of:
66, 98, 54, 92, 87, 63, 72.
Find a certain frequency distribution, the value of mean and mode are 54.6 and 54 respectively. Find the value of median.
Consider the data:
| Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 205 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
The difference of the upper limit of the median class and the lower limit of the modal class is:
