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प्रश्न
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
The median of the following data is 50. Find the values of ‘p’ and ‘q’, if the sum of all frequencies is 90. Also find the mode of the data.
Marks obtained | Number of students |
20 – 30 | p |
30 – 40 | 15 |
40 – 50 | 25 |
50 – 60 | 20 |
60 – 70 | q |
70 – 80 | 8 |
80 – 90 | 10 |
उत्तर
The given series is in inclusive form. Converting it to exclusive form and preparing the cumulative frequency table, we have
Class interval | Frequency (fi ) | Cumulative Frequency (c.f.) |
20 – 30 | p | p |
30 – 40 | 15 | p + 15 |
40 – 50 | 25 | p + 40 |
50 – 60 | 20 | p + 60 |
60 – 70 | q | p + q + 60 |
70 – 80 | 8 | p + q + 68 |
80 – 90 | 10 | p + q + 78 |
78 + p + q = 90 |
Median = 50It lies in the interval 50 – 60, so the median class is 50 – 60.
Now, we have
l = 50, h = 10, f = 20, F = p + 40, N = 90
We know that
Median = `"l" + {("N"/2 - "f")/"f"} xx "h"`
`50 = 50 + (45 - ("p" + 40))/20xx10`
⇒ 0 = `(5 - "p")/2`
⇒ p = 5
And,
p + q + 78 = 90
⇒ p + q = 12
⇒ q = 12 - 5 = 7
Model = `"l" + ("f"_1 - "f"_0)/(2"f"_1 - "f"_0 - "f"_2)."h"`
= `40 + (25 - 15)/(2(25) - 15 - 20)xx10`
= `40 + 100/15`
= 40 + 6.67
= 46.67
संबंधित प्रश्न
The mean of following numbers is 68. Find the value of ‘x’. 45, 52, 60, x, 69, 70, 26, 81 and 94. Hence, estimate the median.
The table below shows the salaries of 280 persons :
Salary (In thousand Rs) | No. of Persons |
5 – 10 | 49 |
10 – 15 | 133 |
15 – 20 | 63 |
20 – 25 | 15 |
25 – 30 | 6 |
30 – 35 | 7 |
35 – 40 | 4 |
40 – 45 | 2 |
45 – 50 | 1 |
Calculate the median salary of the data.
The marks obtained by 19 students of a class are given below:
27, 36, 22, 31, 25, 26, 33, 24, 37, 32, 29, 28, 36, 35, 27, 26, 32, 35 and 28.
Find:
- Median
- Lower quartile
- Upper quartile
- Inter-quartile range
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Age (in years) | 11 | 12 | 13 | 14 | 15 | 16 |
Frequency | 2 | 4 | 6 | 10 | 8 | 7 |
Given below is the number of units of electricity consumed in a week in a certain locality:
Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 200 |
Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
Calculate the median.
Calculate the median from the following data:
Height(in cm) | 135 - 140 | 140 - 145 | 145 - 150 | 150 - 155 | 155 - 160 | 160 - 165 | 165 - 170 | 170 - 175 |
Frequency | 6 | 10 | 18 | 22 | 20 | 15 | 6 | 3 |
Below is the given frequency distribution of words in an essay:
Number of words | Number of Candidates |
600 - 800 | 12 |
800 - 1000 | 14 |
1000 - 1200 | 40 |
1200 - 1400 | 15 |
1400 - 1600 | 19 |
Find the mean number of words written.
Calculate the median of the following distribution:
No. of goals | 0 | 1 | 2 | 3 | 4 | 5 |
No. of matches | 2 | 4 | 7 | 6 | 8 | 3 |
The median of an ungrouped data and the median calculated when the same data is grouped are always the same. Do you think that this is a correct statement? Give reason.
Will the median class and modal class of grouped data always be different? Justify your answer.