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Questions
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
The median of the following data is 50. Find the values of ‘p’ and ‘q’, if the sum of all frequencies is 90. Also find the mode of the data.
Marks obtained | Number of students |
20 – 30 | p |
30 – 40 | 15 |
40 – 50 | 25 |
50 – 60 | 20 |
60 – 70 | q |
70 – 80 | 8 |
80 – 90 | 10 |
Solution
The given series is in inclusive form. Converting it to exclusive form and preparing the cumulative frequency table, we have
Class interval | Frequency (fi ) | Cumulative Frequency (c.f.) |
20 – 30 | p | p |
30 – 40 | 15 | p + 15 |
40 – 50 | 25 | p + 40 |
50 – 60 | 20 | p + 60 |
60 – 70 | q | p + q + 60 |
70 – 80 | 8 | p + q + 68 |
80 – 90 | 10 | p + q + 78 |
78 + p + q = 90 |
Median = 50It lies in the interval 50 – 60, so the median class is 50 – 60.
Now, we have
l = 50, h = 10, f = 20, F = p + 40, N = 90
We know that
Median = `"l" + {("N"/2 - "f")/"f"} xx "h"`
`50 = 50 + (45 - ("p" + 40))/20xx10`
⇒ 0 = `(5 - "p")/2`
⇒ p = 5
And,
p + q + 78 = 90
⇒ p + q = 12
⇒ q = 12 - 5 = 7
Model = `"l" + ("f"_1 - "f"_0)/(2"f"_1 - "f"_0 - "f"_2)."h"`
= `40 + (25 - 15)/(2(25) - 15 - 20)xx10`
= `40 + 100/15`
= 40 + 6.67
= 46.67
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