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प्रश्न
The ages of 37 students in a class are given in the following table:
Age (in years) | 11 | 12 | 13 | 14 | 15 | 16 |
Frequency | 2 | 4 | 6 | 10 | 8 | 7 |
उत्तर
Age (in years) |
Frequency | Cumulative Frequency |
11 | 2 | 2 |
12 | 4 | 6 |
13 | 6 | 12 |
14 | 10 | 22 |
15 | 8 | 30 |
16 | 7 | 37 |
Number of terms = 37
Median = `(37 + 1^(th))/2` term = 19th term
Median = 14
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संबंधित प्रश्न
The following table shows ages of 3000 patients getting medical treatment in a hospital on a particular day :
Age (in years) | No. of Patients |
10-20 | 60 |
20-30 | 42 |
30-40 | 55 |
40-50 | 70 |
50-60 | 53 |
60-70 | 20 |
Find the median age of the patients.
If `sumf_ix_i=75 and sumfi=15` , then find the mean x .
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Rent (in Rs.): | 15 - 25 | 25 - 35 | 35 - 45 | 45 - 55 | 55 - 65 | 65 - 75 | 75 - 85 | 85 - 95 |
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Variable: | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
Frequency: | 12 | 30 | - | 65 | - | 25 | 18 |
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(i) Using the median formula fill up missing frequencies.
(ii) Calculate the AM of the completed distribution.
If the median of the following data is 32.5, find the missing frequencies.
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Frequency: | f1 | 5 | 9 | 12 | f2 | 3 | 2 | 40 |
A survey regarding the height (in cm) of 51 girls of class X of a school was conducted and the following data was obtained:
Height in cm | Number of Girls |
Less than 140 | 4 |
Less than 145 | 11 |
Less than 150 | 29 |
Less than 155 | 40 |
Less than 160 | 46 |
Less than 165 | 51 |
Find the median height.
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0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
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40 | 80 | 62 | 38 | 30 |
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Speed (km/h) | 85 – 100 | 100 – 115 | 115 – 130 | 130 – 145 |
Number of cars | 5 | 8 | 13 | 9 |
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1000 – 1500 | 1500 – 2000 | 2000 – 2500 | 2500 – 3000 | 3000 – 3500 | 3500 – 4000 | 4000 – 4500 | 4500 – 5000 |
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