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प्रश्न
After 2 hours, a radioactive substance becomes `(1/16)^"th"` of original amount. Then the half life ( in min) is
पर्याय
60 minutes
120 minutes
30 minutes
15 minutes
उत्तर
30 minutes
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संबंधित प्रश्न
Derive the relation between half life and rate constant for a first order reaction
Sucrose decomposes in acid solution to give glucose and fructose according to the first order rate law. The half life of the reaction is 3 hours. Calculate fraction of sucrose which will remain after 8 hours.
For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.
A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.
(log 2 = 0.3010)
The half-life period of zero order reaction A → product is given by
(a) `([A]_0)/k`
(b) `0.693/k`
(c) `[A]_0/(2k)`
(d) `(2[A]_0)/k`
The half life period of a first order reaction is 6. 0 h . Calculate the rate constant
Define half life of a reaction.
Show that for a first order reaction half life is independent of initial concentration.
Obtain a relation, `k_2/k_1 = ((t_(1/2))_2)/((t_(1/2))_1)`, where k1 and k2 are rate constants while (t1/2)1 and (t1/2)2 are half-life periods of the first order reaction at temperatures T1 and T2 respectively. Write the relation for activation energy.
Show that the half-life of zero order reaction is `t_(1/2) = ([A]_0)/(2k)`.
