Advertisements
Advertisements
प्रश्न
AM is a median of a triangle ABC.
Is AB + BC + CA > 2 AM?
(Consider the sides of triangles ΔABM and ΔAMC.)
उत्तर
In a triangle, the sum of the lengths of either two sides is always greater than the third side.
In ΔABM,
AB + BM > AM ...(i)
Similarly, in ΔACM,
AC + CM > AM ...(ii)
Adding equation (i) and (ii),
AB + BM + MC + AC > AM + AM
AB + BC + AC > 2AM
Yes, the given expression is true.
APPEARS IN
संबंधित प्रश्न
Is there a triangle whose sides have lengths 10.2 cm, 5.8 cm, and 4.5 cm?
The lengths of two sides of a triangle are 6 cm and 8 cm. Between which two numbers can the length of the third side fall?
The sides of a triangle have lengths (in cm) 10, 6.5 and a, where a is a whole number. The minimum value that a can take is ______.
In ∆PQR ______.
In ∆PQR, ______.
Which of the following statements is not correct?
If length of two sides of a triangle are 6 cm and 10 cm, then the length of the third side can be ______.
Sum of two sides of a triangle is greater than or equal to the third side.
The difference between the lengths of any two sides of a triangle is smaller than the length of third side.
If the areas of two rectangles are same, they are congruent.