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प्रश्न
An alternating current of frequency 200 rad/s and peak value 1 A is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5H, then the voltage induced in the secondary will be approximately (π = 2217)
पर्याय
471 V
191 V
300 V
220 V
MCQ
उत्तर
191 V
Explanation:
e = `"M"((Delta "i")/(Delta "t"))`
`= 1.5 xx (2l)/("T"//2) = 4xx (1.5l)/"T"`
`= (6 xx 1)/(2pi//200)` = 191 V
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