Question

An alternating current of frequency 200 rad/s and peak value 1 A is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5H, then the voltage induced in the secondary will be approximately (π = 2217)

Options

• 471 V

• 191 V

• 300 V

• 220 V

Answer 1

191 V

Explanation:

e = `"M"((Delta "i")/(Delta "t"))`

`= 1.5 xx (2l)/("T"//2) = 4xx (1.5l)/"T"`

`= (6 xx 1)/(2pi//200)` = 191 V