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An electron with speed v0 << c moves in a circle of radius r0 in a uniform magnetic field. A charged particle is projected in a magnetic field B = (2i + 4j) X 102 T. - Physics

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प्रश्न

An electron with speed v0 << c moves in a circle of radius r0 in a uniform magnetic field. This electron is able to traverse a circular path as the magnetic force acting on the electron is perpendicular to both v0 and B, as shown in the figure. This force continuously deflects the particle sideways without changing its speed and the particle will move along a circle perpendicular to the field. The time required for one revolution of the electron is T0.

A charged particle is projected in a magnetic field B = (2i + 4j) X 102 T. The acceleration of the particle is found to be a = (xi + 2j) m/s2. Find the value of x.

पर्याय

  • 4 ms−2

  • −4 ms−2

  • −2 ms−2

  • 2 ms−2

MCQ
घटनेचा अभ्यास

उत्तर

−4 ms−2

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