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प्रश्न
An element crystallises in bcc lattic with a cell edge of 3 × 10-8cm. The density of the element is 6.89 g cm-3 . calculate the molar mass of element. (NA = 6.022 × 1023 mol-1)
उत्तर
BCC lattic, Z=2
a = 3 × 10-8 cm, d = 6.89 gcm-5
`d = (Zm)/a^3` m=mass of one atom
`m =(6.89xx(3xx10^-8)^3)/2`
`m = (6.89xx27xx10^-24)/2`
molar mas = NA × m
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