Question

An unknown gas 'X' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of 'X' gas when the pressure of gas is doubled at the same temperature is ______.

पर्याय

• 0.08

• 0.04

• 0.02

• 0.92

Answer 1

An unknown gas 'X' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of 'X' gas when the pressure of gas is doubled at the same temperature is 0.08.

Explanation:

Mole fraction of gas X in solution

= 0.04

Pressure = 2.5 bar

Let p₁ = P₀X₁

2.5 = 0.04 P₀    ...(i)

Let pressure be doubled, then p₂

5.0 = X₂P₀    ...(ii)

Dividing Eqn ii by eqn I, we get

5.0/2.5 = X_2/0.04

2 × 0.04 = X₂

X₂ = 0.08