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Question
An unknown gas 'X' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of 'X' gas when the pressure of gas is doubled at the same temperature is ______.
Options
0.08
0.04
0.02
0.92
MCQ
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Solution
An unknown gas 'X' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of 'X' gas when the pressure of gas is doubled at the same temperature is 0.08.
Explanation:
Mole fraction of gas X in solution
= 0.04
Pressure = 2.5 bar
Let p1 = P0X1
2.5 = 0.04 P0 ...(i)
Let pressure be doubled, then p2
5.0 = X2P0 ...(ii)
Dividing Eqn ii by eqn I, we get
5.0/2.5 = X2/0.04
2 × 0.04 = X2
X2 = 0.08
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