Question

Answer the followiiig questions: 
Calculate the boiling point of urea solution when 6 g of urea is dissolved in 200 g of water.
(Kb for water = 0.52 K kg mol–1, bolining point of pure water = 373 K, mol. wt. of urea = 60) 

Answer 1

${\displaystyle T_b^o}$= 373 K      M.W. of urea  = 60 g/mol

kb = 0.52  K  kg/mol 
W_urea = 6g
W_solvent = 200g
T_b = ? 
As we know 
${\displaystyle \Delta T_b=K_b\times \frac{W_2}{M_2}\times \frac{1000}{W_1}}$

${\displaystyle Tb-T_b^0=Kb\times \frac{W_2}{M_2}\times \frac{1000}{W_1}}$ 

${\displaystyle T_b-373= 0.52\times \frac{6}{60}\times \frac{1000}{200}}$

`T<sub>b</sub> = 373.25 K`