Advertisements
Advertisements
प्रश्न
Calculate the boiling point of urea solution when 8.0g of urea is dissolved in 250g of water. Boiling point of pure water is 373K.
(kb of water = 0.52 K kg mol-1, molecular mass of urea = 60 g mol-1)
उत्तर
To calculate the boiling point of a urea solution, the boiling point elevation formula:
ΔTb = i × kb × m
where,
ΔTb = 0.277 K (boiling point elevation)
i = Van't Hoff factor
Kb = 0.52 K·kg/mol
m = molality of the solution.
As we know,
`"T"_"solution" = "T"_"pure solvent" + Δ"T"_"b"`
`"T"_"solution"` = 373 K + 0.277 K
`"T"_"solution"` = 373.277 K
∴ boiling point of the urea solution is 373.277 K
APPEARS IN
संबंधित प्रश्न
Fill in the blanks by choosing the appropriate word/words from those given in the brackets:
(more than, primary, cathode, Lucas reagent, two, four, less than, Grignard’s reagent, tertiary anode, zero, equal to, three)
The elevation of boiling point of 0.5 M K2SO4 solution is ________ that of 0.5 M urea solution. The elevation of boiling point of 0.5 M KCl solution is _______ that of 0·5 M K2SO4 solution.
Answer the followiiig questions:
Calculate the boiling point of urea solution when 6 g of urea is dissolved in 200 g of water.
(Kb for water = 0.52 K kg mol–1, bolining point of pure water = 373 K, mol. wt. of urea = 60)
