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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Answer the following: Find the trigonometric functions of : −180° - Mathematics and Statistics

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प्रश्न

Answer the following:

Find the trigonometric functions of :

−180°

बेरीज

उत्तर

Trigonometric Functions of (−180°) :

Let m∠XOA = (−180°)

Its terminal arm (ray OA) intersects the standard unit circle at P(– 1, 0).

∴ x = – 1 and y = 0

sin (−180°) = y = 0

cos (−180°) = x = – 1

tan (−180°) = `y/x`

= `0/(-1)`

= 0

cosec (−180°) = `1/y`

= `1/0`, which is not defined

sec (−180°) = `1/x = 1/(-1)` = – 1

cot (−180°) = `x/y = (-1)/0`, which is not defined.

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Trigonometric Functions of Specific Angles
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Trigonometry - 1 - MISCELLANEOUS EXERCISE - 2 [पृष्ठ ३३]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
पाठ 2 Trigonometry - 1
MISCELLANEOUS EXERCISE - 2 | Q II) 1) ix) | पृष्ठ ३३
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