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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the trigonometric functions of 120°. - Mathematics and Statistics

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प्रश्न

Find the trigonometric functions of 120°.

बेरीज

उत्तर


Let m∠XOA = 120°

Its terminal arm (ray OA) intersects the standard unit circle in P (x, y). 

Draw seg PM perpendicular to the X-axis.

Δ OMP is a 30° - 60° - 90° triangle

OP = 1

PM = `sqrt3/2`OP

`= sqrt3/2(1)`

`= sqrt3/2`

OM = `1/2` OP

`= 1/2 (1)`

`= 1/2`

Since point P lies in the 2nd quadrant, x < 0, y > 0

∴ x = - OM = `- 1/2` and y = PM = `sqrt3/2`

∴ P ≡ `((-1)/2, sqrt3/2)`

sin 120° = y = `sqrt3/2`

cos 120° = x = `- 1/2`

tan 120° = `y/x = (sqrt3/2)/(-1/2) = - sqrt3`

cosec 120° = `1/y = 1/(sqrt3/2) = 2/sqrt3`

sec 120° = `1/x = 1/(- 1/2)` = - 2

cot 120° = `x/y = (-1/2)/(sqrt3/2) = - 1/sqrt3`

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Trigonometric Functions of Specific Angles
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Trigonometry - 1 - MISCELLANEOUS EXERCISE - 2 [पृष्ठ ३३]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
पाठ 2 Trigonometry - 1
MISCELLANEOUS EXERCISE - 2 | Q II) 1) ii) | पृष्ठ ३३
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