Advertisements
Advertisements
प्रश्न
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.
उत्तर
Radius of bigger circle = R
Radius of smaller circle = r
Area = A = π(R2 - r2)
⇒ A = π(R2 - r2)
⇒ `"A"/pi = "R"^2 - "r"^2`
⇒ r2 = `"R"^2 - "A"/pi`
⇒ r = `sqrt("R"^2 - "A"/pi)`
Putting A = 88cm2 and R = 8cm
⇒ r = `sqrt(8^2 - 88/(22/7)`
= 6cm.
APPEARS IN
संबंधित प्रश्न
The arithmetic mean M of the five numbers a, b, c, d, e is equal to their sum divided by the number of quantities. Express it as a formula.
Make a the subject of formula S = `"ut" + (1)/(2)"at"^2`
Make r2 the subject of formula `(1)/"R" = (1)/"r"_1 + (1)/"r"_2`
Make N the subject of formula I = `"NG"/("R" + "Ny")`
Make d the subject of formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`
Make R2 the subject of formula R2 = 4π(R12 - R22)
If b = `(2"a")/("a" - 2)`, and c = `(4"b" - 3)/(3"b" + 4)`, then express c in terms of a.
Make y the subject of the formula x = `(1 - y^2)/(1 + y^2)`. Find y if x = `(3)/(5)`
Make c the subject of the formula a = b(1 + ct). Find c, when a = 1100, b = 100 and t = 4.
The total energy E possess by a body of Mass 'm', moving with a velocity 'v' at a height 'h' is given by: E = `(1)/(2) "m" "u"^2 + "mgh"`. Make 'm' the subject of formula.