Advertisements
Advertisements
प्रश्न
Area of triangle MNO in the figure is ______.
पर्याय
`1/2` MN × NO
`1/2` NO × MO
`1/2` MN × OQ
`1/2` NO × OQ
उत्तर
Area of triangle MNO in the figure is `underlinebb(1/2 NO xx OQ)`.
Explanation:
MNO is a triangle
We know that, area of triangle = `1/2` (base × height)
= `1/2` × NO × OQ
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle PQR with Q(3,2) and the mid-points of the sides through Q being (2,−1) and (1,2).
The vertices of ∆ABC = are A (4, 6), B(1, 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively such that `\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{4}` .Calculate the area of ∆ADE and compare it with the area of ∆ABC
Find the area of the quadrilaterals, the coordinates of whose vertices are
(−3, 2), (5, 4), (7, −6) and (−5, −4)
Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200 cm ?
Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42cm ?
Find the area of ΔABC whose vertices are:
A(10,-6) , B (2,5) and C(-1,-3)
Find the value of y for which the points A(-3, 9), B(2,y) and C(4,-5) are collinear.
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| 5 feet | ? | 20 sq.feet |
The value of the determinant `abs((1,"x","x"^3),(1,"y","y"^3),(1,"z","z"^3))` is ____________.
If the points (a1, b1), (a2, b2) and(a1 + a2, b1 + b2) are collinear, then ____________.
