Advertisements
Advertisements
प्रश्न
By how much is 3x3 – 2x2y + xy2 -y3 less than 4x3 – 3x2y – 7xy2 +2y3
उत्तर
We can get the required results by substracting
3x3 – 2x2y + xy2 -y3 from 4x3 – 3x2y – 7xy2 +2y3
= (4x3 – 3x2y – 7xy2 +2y3 ) - (3x3 – 2x2y + xy2 -y3)
= 4x3 – 3x2y – 7xy2 +2y3 - 3x3 + 2x2y - xy2 + y3
= 4x3 - 3x3 – 3x2y + 2x2y – 7xy2 - xy2 +2y3 + y3
= x3 - x2y - 8xy2 + 3y3
APPEARS IN
संबंधित प्रश्न
Subtract: - 5a - 2b from b + 6c
Subtract: 5a - 3b + 2c from 4a - b - 2c
Find the excess of 4m2 + 4n2 + 4p2 over m2+ 3n2 – 5p2
Simplify: 3(4y - 10) 2(y - 1)
Copy and complete the following multiplication:
4x3 − 10x2 + 6x − 8
× 3 + 2x − x2
Simplify: `"k"/2 + "k"/3 + "2k"/5`
Simplify: `"4a"/7 + "2a"/3 - "a"/7`
Simplify: `"x" + "x"/2 + "x"/3`
Simplify: `"x"/5 + "x + 1"/2`
Simplify: `(5 ("x" - 4))/3 + (2(5x - 3))/5 + (6(x - 4))/7`
