Advertisements
Advertisements
Question
By how much is 3x3 – 2x2y + xy2 -y3 less than 4x3 – 3x2y – 7xy2 +2y3
Solution
We can get the required results by substracting
3x3 – 2x2y + xy2 -y3 from 4x3 – 3x2y – 7xy2 +2y3
= (4x3 – 3x2y – 7xy2 +2y3 ) - (3x3 – 2x2y + xy2 -y3)
= 4x3 – 3x2y – 7xy2 +2y3 - 3x3 + 2x2y - xy2 + y3
= 4x3 - 3x3 – 3x2y + 2x2y – 7xy2 - xy2 +2y3 + y3
= x3 - x2y - 8xy2 + 3y3
APPEARS IN
RELATED QUESTIONS
Subtract: 2x2 - 7xy - y2 from 3x2 - 5xy + 3y2
Subtract: a2 - 3ab - 6b2 from 2b2 - a2 + 2ab
Subtract the sum of 3a2 – 2a + 5 and a2 – 5a – 7 from the sum of 5a2 -9a + 3 and 2a – a2 – 1
The perimeter of a triangle is 14a2 + 20a + 13. Two of its sides are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
Simplify: 4x + 7y - (5y - 8) - 2x
Copy and complete the following multi-plication:
9x + 5y
× - 3xy
Evaluate: (a + 1)(a2 - a + 1) and (a - 1)(a2 + a + 1)
Multiply: mn4, m3n and 5m2n3
Multiply: x3 - 3y3 and 4x2y2
Simplify: `"2a + 1"/3 + "3a - 1"/2`