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प्रश्न
Calculate the co-ordinates of the point P which divides the line segment joining: A (–4, 6) and B (3, –5) in the ratio 3 : 2
उत्तर
Let the co-ordinates of the point P be (x, y).
`x = (m_1x_2 + m_2x_1)/(m_1 + m_2)`
= `(3 xx 3 + 2 xx (-4))/(3 + 2)`
= `1/5`
`y = (m_1y_2 + m_2y_1)/(m_1 + m_2)`
= `(3 xx (-5) + 2 xx 6)/(3 + 2)`
= `(-3)/5`
Thus, the co-ordinates of point P are `(1/5, (-3)/5)`
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संबंधित प्रश्न
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= `a(1/t^2 + 1) = (a(t^2 + 1))/t^2`
Now `(1)/"SP" + (1)/"SQ" = (1)/(a(t^2 + 1)) + (1 xx t^2)/(a(t^2 + 1)`
= `((1 + t^2))/(a(t^2 + 1)`
`(1)/"SP" + (1)/"SQ" = (1)/a`.
If the line joining the points A(4, - 5) and B(4, 5) is divided by the point P such that `"AP"/"AB" = (2)/(5)`, find the coordinates of P.
In the following figure line APB meets the X-axis at A, Y-axis at B. P is the point (4, -2) and AP: PB = 1: 2. Write down the coordinates of A and B.
Determine the centre of the circle on which the points (1, 7), (7 – 1), and (8, 6) lie. What is the radius of the circle?
