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प्रश्न
Calculate the mass of 1022 atoms of sulphur.
[Atomic mass: S = 32, C = 12 and O = 16 and Avogadro's number = 6 × 1023]
उत्तर
6.022 × 1023 atoms of sulphur weight = 32 g
1 atom of sulphur weigh = `32/(6.022 xx 10^23)`
1022 atoms of sulphur weigh = `32/(6.022 xx 10^23) xx 10^22`
= 0.531 g
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संबंधित प्रश्न
State Avogadro's Law.
If 150 cc of gas A contains X molecules, how many molecules of gas B will be present in 75 cc of B?. The gases A and B are under the same conditions of temperature and pressure.
State: Avogadro's law
Define atomicity of a gas.
Samples of the gases O2, N2, CO2 and CO under the same conditions of temperature and pressure contain the same number of molecules represented by X. The molecules of Oxygen, occupy V litres and have a mass of 8 g. Under the same conditions of temperature and pressure:
In answering the above questions, which law have you used?
A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the mass of nitrogen gas in the cylinder.
The gases chlorine, nitrogen, ammonia and sulphur dioxide are collected under the same conditions of temperature and pressure. The following table gives the volumes of gases collected and the number of molecules (x) in 20 litres of nitrogen. You are to complete the table giving the number of molecules in the other gases in terms of x.
| Gas | Volume (in litres) | Number of molecules |
| Chlorine | 10 | x |
| Nitrogen | 20 | |
| Ammonia | 20 | |
| Sulphur dioxide | 5 |
- If 150 cc of gas A contains X molecules, how many molecules of gas B will be present in 75 cc of B? The gases A and B are under the same conditions of temperature and pressure.
- Name the law on which the above problem is based.
Calculate :
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