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प्रश्न
Calculate the mean of the following data:
| Class | 4 – 7 | 8 – 11 | 12 – 15 | 16 – 19 |
| Frequency | 5 | 4 | 9 | 10 |
उत्तर
Since, given data is not continuous, so we subtract 0.5 from the lower limit and add 0.5 in the upper limit of each class.
Now, we first find the class mark xi of each class and then proceed as follows.
| Class | Class marks `(bb(x_i))` |
Frequency `(bb(f_i))` |
`bb(f_ix_i)` |
| 3.5 – 7.5 | 5.5 | 5 | 27.5 |
| 7.5 – 11.5 | 9.5 | 4 | 38 |
| 11.5 – 15.5 | 13.5 | 9 | 121.5 |
| 15.5 – 19.5 | 17.5 | 10 | 175 |
| `sumf_i = 28` | `sumf_ix_i = 362` |
Therefore, mean `(barx) = (sumf_ix_i)/(sumf_i)`
= `362/28`
= 12.93
Hence, mean of the given data is 12.93.
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