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प्रश्न
The table below shows the daily expenditure on food of 25 households in a locality.
Daily expenditure (in Rs) | 100 − 150 | 150 − 200 | 200 − 250 | 250 − 300 | 300 − 350 |
Number of households | 4 | 5 | 12 | 2 | 2 |
Find the mean daily expenditure on food by a suitable method.
उत्तर
To find the class mark (xi) for each interval, the following relation is used:
Let the assumed mean, a = 225
Class size, h = 50
= `u_i = (x_i - a)/h`
= `(x_i - 225)/50`
Taking 225 as the assumed mean (a), di, ui, fiui are calculated as follows.
Daily expenditure (in Rs) | fi | xi | di = xi − 225 | `u_i=(x_i-225)/50` | fiui |
100 − 150 | 4 | 125 | − 100 | − 2 | − 8 |
150 − 200 | 5 | 175 | − 50 | − 1 | − 5 |
200 − 250 | 12 | 225 | 0 | 0 | 0 |
250 − 300 | 2 | 275 | 50 | 1 | 2 |
300 − 350 | 2 | 325 | 100 | 2 | 4 |
Total | 25 | -7 |
From the table, we obtain:
`sumf_i = 25`
`sumf_iu_i = -7`
`"Mean " barx = a+ ((sumf_1u_i)/(sumf_i))xh`
= `225 + ((-7)/25)xx(50)`
= 225 − 14
= 211
Therefore, mean daily expenditure on food is Rs 211.
संबंधित प्रश्न
Consider the following distribution of daily wages of 50 worker of a factory.
Daily wages (in Rs) |
100 − 120 |
120 − 140 |
140 −1 60 |
160 − 180 |
180 − 200 |
Number of workers |
12 |
14 |
8 |
6 |
10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
Find the value of p for the following distribution whose mean is 16.6
x | 8 | 12 | 15 | P | 20 | 25 | 30 |
f | 12 | 16 | 20 | 24 | 16 | 8 | 4 |
The following table gives the number of children of 150 families in a village. Find the average number of children per family.
No. of children (x) | 0 | 1 | 2 | 3 | 4 | 5 |
No. of families (f) | 10 | 21 | 55 | 42 | 15 | 7 |
The following distribution gives the number of accidents met by 160 workers in a factory during a month.
No. of accidents(x) | 0 | 1 | 2 | 3 | 4 |
No. of workers (f) | 70 | 52 | 34 | 3 | 1 |
Find the average number of accidents per worker.
The following table gives the distribution of total household expenditure (in rupees) of manual workers in a city. Find the average expenditure (in rupees) per household.
Expenditure (in rupees) (x1) |
Frequency(f1) |
100 - 150 | 24 |
150 - 200 | 40 |
200 - 250 | 33 |
250 - 300 | 28 |
300 - 350 | 30 |
350 - 400 | 22 |
400 - 450 | 16 |
450 - 500 | 7 |
Find the mean of each of the following frequency distributions: (5 - 14)
Class interval | 0 - 6 | 6 - 12 | 12 - 18 | 18 - 24 | 24 - 30 |
Frequency | 6 | 8 | 10 | 9 | 7 |
Find the mean of each of the following frequency distributions
Class interval | 10 - 30 | 30 - 50 | 50 - 70 | 70 - 90 | 90 - 110 | 110 - 130 |
Frequency | 5 | 8 | 12 | 20 | 3 | 2 |
For the following distribution, calculate mean using all suitable methods:
Size of item | 1 - 4 | 4 - 9 | 9 - 16 | 16 - 27 |
Frequency | 6 | 12 | 26 | 20 |
The mean of following frequency distribution is 54. Find the value of p.
Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 |
Frequency | 7 | p | 10 | 9 | 13 |
Find the mean age from the following frequency distribution:
Age (in years) | 25 – 29 | 30 – 34 | 35 – 39 | 40 – 44 | 45 – 49 | 50 – 54 | 55 – 59 |
Number of persons | 4 | 14 | 22 | 16 | 6 | 5 | 3 |
The following table shows the income of farmers in a grape season. Find the mean of their income.
Income
(Thousand Rupees)
|
20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 |
Farmers | 10 | 11 | 15 | 16 | 18 | 14 |
There are three dealers A, B and C in Maharashtra. Suppose, the trade of each of them in september 2018 was as shown in the following table.
The rate of GST on each transaction was 5%.
Read the table and answer the questions below it.
Dealer | GST collected on the sale |
GST paid at the time of purchase |
ITC | Tax paid to the Govt. |
Taxbalance with the Govt. |
A | Rs.5000 | Rs. 6000 | Rs. 5000 | Rs. 0 | Rs. 1000 |
B | Rs 5000 | Rs. 4000 | Rs. 4000 | Rs. 1000 | Rs. 0 |
C | Rs.5000 | Rs. 5000 | Rs. 5000 | Rs. 0 | Rs. 0 |
(i) How much amount did the dealer A get by sale ?
(ii) For how much amount did the dealer B buy the articles ?
(iii) How much is the balance of CGST and SGST left with the government that was paid by A ?
The arithmetic mean of 1, 2, 3, ... , n is
The weekly wages of 120 workers in a factory are shown in the following frequency distribution table. Find the mean of the weekly wages.
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|
0 - 2000 | 2000 - 4000 | 4000 - 6000 | 6000 - 8000 |
No. of workers | 15 | 35 | 50 | 20 |
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Find the mean of the following distribution:
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f | 5 | 10 | 10 | 7 | 8 |
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Find the mean number of pages written per day.
The daily income of a sample of 50 employees are tabulated as follows:
Income (in Rs) |
1 – 200 | 201 – 400 | 401 – 600 | 601 – 800 |
Number of employees |
14 | 15 | 14 | 7 |
Find the mean daily income of employees.