Question

Calculate the molarity of the following solution: 

30 mL of 0.5 M \[\ce{H2SO4}\] diluted to 500 mL.

Answer 1

Number of moles present in 500 mL of 0.5 M \[\ce{H2SO4}\] = 0.5 mol

∴ V₁ = 30 ml, M₁ = 0.5 M

V₂ = 500 ml, M₂ = ?

∴ M₁V₁ = M₂V₂

⇒ 0.5 M × 30 ml = M₂ × 500 ml

⇒ M₂ = `(0.5xx30)/500`

⇒ `15/500`

⇒ 0.03 M