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प्रश्न
Calculate the oxidation number of the underlined atom.
H2S4O6
उत्तर
H2S4O6
Oxidation number of H = +1
Oxidation number of O = –2
H2S4O6 is a neutral molecule.
∴ Sum of the oxidation numbers of all atoms = 0
∴ 2 × (Oxidation number of H) + 4 × (Oxidation number of S) + 6 × (Oxidation number of O) = 0
∴ 2 × (+1) + 4 × (Oxidation number of S) + 6 × (–2) = 0
∴ 4 × (Oxidation number of S) + 2 – 12 = 0
∴ 4 × (Oxidation number of S) = + 10
∴ Oxidation number of S =`+10/4`
∴ Oxidation number of S in H2S4O6 = +2.5
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