Advertisements
Advertisements
प्रश्न
Can copper sulphate solution be stored in an iron vessel? Explain.
उत्तर
Higher the standard reduction potential (Eº) value, greater the tendency of the species to accept electrons and undergo reduction.
Cu2++2e-→Cu, Eº = + 0.337 V ; Fe2+ + 2e- → Fe, Eº = - 0.440 V
Therefore, Cu2+ has a greater tendency to undergo reduction than Fe2+ or Fe can reduce (or displace) Cu2+ ions from its salt solution.
Fe(s) +Cu2(aq) → Fe2(aq) + Cu(s)
Hence, copper sulphate solution cannot be stored in an iron vessel as the iron vessel dissolves forming Fe2+ ions and Cu2+ ions from copper sulphate solution forms Cu.
APPEARS IN
संबंधित प्रश्न
Draw a neat and well labelled diagram of primary reference electrode.
Arrange the following reducing agents in the order of increasing strength under standard state conditions. Justify the answer
Element |
Al(s) |
Cu(s) |
Cl(aq) |
Ni(s) |
Eo |
-1.66V |
0.34V |
1.36V |
-0.26V |
Calculate Ecell and ΔG for the following at 28°C :
Mg(s) + Sn2+( 0.04M ) → Mg2+( 0.06M ) + Sn(s)
E°cell = 2.23V. Is the reaction spontaneous ?
The standard e.m.f of the following cell is 0.463 V
`Cu|Cu_(1m)^(++)`
What is the standard potential of Cu electrode?
(A) 1.137 V
(B) 0.337 V
(C) 0.463 V
(D) - 0.463 V
Calculate E°cell for the following reaction at 298 K:
2Al(s) + 3Cu+2(0.01M) → 2Al+3(0.01M) + 3Cu(s)
Given: Ecell = 1.98V
Calculate emf of the following cell at 25°C:
\[\ce{Sn/Sn^2+ (0.001 M) || H+ (0.01 M) | H2_{(g)} (1 bar) | Pt_{(s)}}\]
Given: \[\ce{E^\circ(Sn^2+/sn) = -0.14 V, E^\circ H+/H2 = 0.00 V (log 10 = 1)}\]
Calculate e.m.f of the following cell at 298 K:
2Cr(s) + 3Fe2+ (0.1M) → 2Cr3+ (0.01M) + 3 Fe(s)
Given: E°(Cr3+ | Cr) = – 0.74 VE° (Fe2+ | Fe) = – 0.44 V
Calculate emf of the following cell at 25 °C :
Fe|Fe2+(0.001 M)| |H+(0.01 M)|H2(g) (1 bar)|Pt (s)
E°(Fe2+| Fe)= −0.44 V E°(H+ | H2) = 0.00 V
Calculate e.m.f. and ∆G for the following cell:
Mg (s) |Mg2+ (0.001M) || Cu2+ (0.0001M) | Cu (s)
`"Given :" E_((Mg^(2+)"/"Mg))^0=−2.37 V, E_((Cu^(2+)"/"Cu))^0=+0.34 V.`
Given the standard electrode potentials,
\[\ce{K+/K}\] = −2.93 V, \[\ce{Ag+/Ag}\] = 0.80 V,
\[\ce{Hg^{2+}/Hg}\] = 0.79 V
\[\ce{Mg^{2+}/Mg}\] = −2.37 V, \[\ce{Cr^{3+}/Cr}\] = −0.74 V
Arrange these metals in their increasing order of reducing power.
In the representation of the galvanic cell, the ions in the same phase are separated by a _______.
Draw a neat and labelled diagram of the lead storage battery.
Calculate the emf of the following cell at 25°C :
Galvanic or a voltaic cell converts the chemical energy liberated during a redox reaction to ____________.
Which cell will measure standard electrode potential of copper electrode?
The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called ______.
The positive value of the standard electrode potential of Cu2+/Cu indicates that:
(i) this redox couple is a stronger reducing agent than the H+/H2 couple.
(ii) this redox couple is a stronger oxidising agent than H+/H2 .
(iii) Cu can displace H2 from acid.
(iv) Cu cannot displace H2 from acid.
What does the negative sign in the expression `"E"^Θ ("Zn"^(2+))//("Zn")` = − 0.76 V mean?
Which reference electrode is used to measure the electrode potential of other electrodes?
Consider the figure and answer the following question.
If cell ‘A’ has ECell = 0.5V and cell ‘B’ has ECell = 1.1V then what will be the reactions at anode and cathode?
The standard electrode potential of the two half cells are given below:
\[\ce{Ni^{2+} + 2e^{-} -> Ni, E_0 = - 0.25 Volt}\]
\[\ce{Zn^{2+} + 2e^{-} -> Zn, E_0 = - 0.77 Volt}\]
The voltage of cell formed by combining the two half cells would be?
Which is the correct order of second ionization potential of C, N, O and F in the following?
Standard electrode potential of three metals X, Y and Z are – 1.2 V, + 0.5 V and – 3.0 V, respectively. The reducing power of these metals will be: