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प्रश्न
Characol pieces of tree is found from an archeological site. The carbon-14 content of this characol is only 17.5% that of equivalent sample of carbon from a living tree. What is the age of tree?
उत्तर
activity R = 17.5%
T1/2 = 5730 yr
The activity of the sample R = R0 e-λt
e-λt = R0/R
By taking the algorithm on bothsides, we get
t = `1/lambda ln ("R"/"R"_circ)`
`"T"_(1/2) = (ln2)/lambda`
t = `("T"_(1/2)/(ln 2) ln ("R"/"R"_circ)`
t = `5730/(ln2) ln (1/0.175) = 14,400` yr
t = `1.44 xx 10^4` yr
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