मराठी

Choose the Correct Answer: Grapes When Placed in a Strong Sugar Solution Shrink Because of __________ - Biology

Advertisements
Advertisements

प्रश्न

Choose the correct answer:

Grapes when placed in a strong sugar solution shrink because of __________

पर्याय

  • diffusion         

  • plasmolysis

  • exosmosis      

  • endosmosis

MCQ

उत्तर

Grapes when placed in a strong sugar solution shrink because of plasmolysis

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Absorption by Roots - Exercise 4 [पृष्ठ ५१]

APPEARS IN

फ्रँक Biology [English] Class 10 ICSE
पाठ 4 Absorption by Roots
Exercise 4 | Q 1.04 | पृष्ठ ५१

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

(a) Mention whether the following statement is true (True) or false (False) 

(b) Correct the false statement by altering the last word only.

A plant cell placed in hypotonic solution gets Plasmolysed. 


Mention whether the following statement is true or false. Correct the false statement by altering the last word only.  

Addition of salt to pickles prevents growth of bacteria because they turn turgid. 


Show by a series of diagrams, the change which a plant cell will undergo when placed in
Hypertonic salt solution


Define the following:

Diffusion


What is the utility of plasmolysis?

Name the condition in which the cell contents are shrunken.

What will happen if a concentrated solution of a fertilizer is given to the potted plants?

Two potato cubes each 1 cm3 in size, were placed separately in two containers (A and B), the container A having water and the other (B) containing concentrated sugar solution. After 24 hours when the cubes were examined, those placed in water were found to be firm and had increased slightly in size and those placed in concentrated sugar solution were found to be soft and somewhat decreased in size. Use the above information to answer the questions that follow:

Account for the softness and decrease in size of the potato cubes which were placed in sugar solution.


In the figure below ‘A’ shows a cell in the normal state and ‘B’ shows the same cell after leaving it in a certain solution for a few minutes.




(i) Describe the change which has occurred in the cell as seen in B.
(ii) Give the technical term for the condition of the cell as reached in B and as it was in A.
(iii) Define the process which led to this condition.
(iv) What was the solution-isotonic, hypotonic or hypertonic, in which the cell was kept?
(v) How can the cell in B, be brought back to its original condition?
(vi) Name the parts numbered 1 to 3.


When a cell in solution shrinks and loses its shape, then the solution is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×