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Comment on the thermodynamic stability of NO(g), given 12NX2(g)+12OX2(g)⟶NO(g); ΔrHθ = 90 kJ mol–1 NO(g)+12OX2(g)⟶NOX2(g) : ΔrHθ= –74 kJ mol–1 - Chemistry

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प्रश्न

Comment on the thermodynamic stability of NO(g), given

\[\ce{1/2 N_2 (g) + 1/2 O2(g) → NO(g)}\]; ΔrHθ = 90 kJ mol–1

\[\ce{NO(g) +1/2 O2(g) → NO2(g)}\] : ΔrHθ= –74 kJ mol–1

टीपा लिहा

उत्तर

The positive value of ΔrH indicates that heat is absorbed during the formation of NO(g). This means that NO(g) has higher energy than the reactants (N2 and O2). Hence, NO(g) is unstable.

The negative value of ΔrH indicates that heat is evolved during the formation of NO2(g) from NO(g)and O2(g). The product, NO2(g) is stabilized with minimum energy.

Hence, unstable NO(g) changes to stable NO2(g).

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Measurement of ∆U and ∆H Calorimetry - ∆H Measurements
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पाठ 6: Thermodynamics - EXERCISES [पृष्ठ १९१]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
पाठ 6 Thermodynamics
EXERCISES | Q 6.21 | पृष्ठ १९१
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