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Karnataka Board PUCPUC Science Class 11

Comment on the thermodynamic stability of NO(g), given 12NX2(g)+12OX2(g)⟶NO(g); ΔrHθ = 90 kJ mol–1 NO(g)+12OX2(g)⟶NOX2(g) : ΔrHθ= –74 kJ mol–1 - Chemistry

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Question

Comment on the thermodynamic stability of NO(g), given

\[\ce{1/2 N_2 (g) + 1/2 O2(g) → NO(g)}\]; ΔrHθ = 90 kJ mol–1

\[\ce{NO(g) +1/2 O2(g) → NO2(g)}\] : ΔrHθ= –74 kJ mol–1

Short Note

Solution

The positive value of ΔrH indicates that heat is absorbed during the formation of NO(g). This means that NO(g) has higher energy than the reactants (N2 and O2). Hence, NO(g) is unstable.

The negative value of ΔrH indicates that heat is evolved during the formation of NO2(g) from NO(g)and O2(g). The product, NO2(g) is stabilized with minimum energy.

Hence, unstable NO(g) changes to stable NO2(g).

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Chapter 6: Thermodynamics - EXERCISES [Page 191]

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NCERT Chemistry - Part 1 and 2 [English] Class 11
Chapter 6 Thermodynamics
EXERCISES | Q 6.21 | Page 191
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