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प्रश्न
Compare the following pair of ratios.
`sqrt80/sqrt48 , sqrt45/sqrt27`
उत्तर
`sqrt80 xx sqrt27 = sqrt (16 xx 5) xx sqrt ( 9 xx 3) = 4sqrt5 xx 3sqrt3 = 12sqrt15`
`sqrt45 xx sqrt48 = sqrt( 9 xx 5) xx sqrt( 16 xx 3) = 3sqrt5 xx 4sqrt3 = 12sqrt15`
Now, `12sqrt15 = 12sqrt15`
`therefore sqrt80/sqrt 48 = sqrt45/sqrt27`
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