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प्रश्न
Complete the following ionic equation:
\[\ce{Cr2O^2-_7 + 14H+ + 6e- ->}\]
रासायनिक समीकरणे/रचना
उत्तर
\[\ce{Cr2O^2-_7 + 14H+ + 6e- -> 2Cr^3+ + 7H2O}\]
Write an unbalanced reaction:
\[\ce{Cr2O^2-_7 + 14H+ + 6e- -> Cr}\]
Balance the atoms other than hydrogen and oxygen:
\[\ce{Cr2O^2-_7 + 14H+ + 6e- -> 2Cr}\]
Balance the oxygen by adding water to the side that needs oxygen:
\[\ce{Cr2O^2-_7 + 14H+ + 6e- -> 2Cr + 7H2O}\]
Balance the charge by adding electrons or charge:
\[\ce{Cr2O^2-_7 + 14H+ + 6e- -> 2Cr^3+}\]
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