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Compute the number of ions present in 5.85 g of sodium chloride - Science

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प्रश्न

Compute the number of ions present in 5.85 g of sodium chloride

बेरीज

उत्तर

1 mole of NaCl = 23 + 35.5

= 58.5 g of NaCl

Number of moles in 5085 g of NaCl

= `5085/58.5`

= 0.1 moles

Each NaCl formula unit=Na++ Cl

= 2 ions

Number of ions = 0.2 × 6.022 × 1023

= 1.2044 × 1023 icons

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पाठ 3: Atoms and Molecules [पृष्ठ २३]

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एनसीईआरटी एक्झांप्लर Science [English] Class 9
पाठ 3 Atoms and Molecules
Q 38. | पृष्ठ २३

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