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Question
Compute the number of ions present in 5.85 g of sodium chloride
Solution
1 mole of NaCl = 23 + 35.5
= 58.5 g of NaCl
Number of moles in 5085 g of NaCl
= `5085/58.5`
= 0.1 moles
Each NaCl formula unit=Na++ Cl–
= 2 ions
Number of ions = 0.2 × 6.022 × 1023
= 1.2044 × 1023 icons
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Express each of the following in kilograms
0.584 g
Express each of the following in kilograms
5.873×10−21g
