Advertisements
Advertisements
प्रश्न
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
बेरीज
उत्तर
`(27)^(2/3)÷(81/16)^(-1/4)=(3^3)^(2/3)÷(3^4/2^4)^(-1/4)`
`=3^(3xx2/3)÷3^(-1/4xx4)/2^(-1/4xx4)=3^2÷3^-1/2^-1`
`=3^2xx2^-1/3^-1`
`=3^(2+1)xx2^-1=3^3xx1/2^+1`
`=(3xx3xx3)/2=27/2=13 1/2`
shaalaa.com
More About Exponents
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Compute:
`1^8xx3^0xx5^3xx2^2`
Compute:
`(27/64)^(-2/3)`
Compute:
`(125)^(-2/3)÷(8)^(2/3)`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
