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प्रश्न
Compute:
`(27/64)^(-2/3)`
बेरीज
उत्तर
`(27/64)^(-2/3)=[[(3^3))/((4^3))]^(-2/3)`
`=3^(3xx-2/3)/4^(3xx(-2)/3)=3^-2/4^-2`
`=4^2/3^2=(4xx4)/(3xx3)=16/9`
`=1 7/9`
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